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2x^2=-17-10x
We move all terms to the left:
2x^2-(-17-10x)=0
We add all the numbers together, and all the variables
2x^2-(-10x-17)=0
We get rid of parentheses
2x^2+10x+17=0
a = 2; b = 10; c = +17;
Δ = b2-4ac
Δ = 102-4·2·17
Δ = -36
Delta is less than zero, so there is no solution for the equation
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